(2x+1)^2=4(x^2+x+1)

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Solution for (2x+1)^2=4(x^2+x+1) equation: 



(2x+1)^2=4(x^2+x+1)

We move all terms to the left:

(2x+1)^2-(4(x^2+x+1))=0



We calculate terms in parentheses: -(4(x^2+x+1)), so:

4(x^2+x+1)

We multiply parentheses

4x^2+4x+4

Back to the equation:

-(4x^2+4x+4)



We get rid of parentheses

-4x^2+(2x+1)^2-4x-4=0

We add all the numbers together, and all the variables

-4x^2-4x+(2x+1)^2-4=0

We move all terms containing x to the left, all other terms to the right

-4x^2-4x+(2x+1)^2=4

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